PRIVATE symbol in PUBLIC namelist
Paul Richard Thomas
paul.richard.thomas@gmail.com
Thu Jun 28 07:02:00 GMT 2007
Janus,
You have found a bug. Logic and Lahey say that it is.
I cannot access a gfortran source today but, if you were to grep part
of the error message, in the fortran source, you would find out where
it is coming from. Then, in addition to checking if the symbol is
private, you then need to check if the symbol is use associated (ie.
if (sym->attr.private && sym->attr.use_assoc). This should yield the
correct behaviour.
I suggest that you submit a PR and fix it:-)
Paul
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