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std::function with std::unique_ptr argument
- From: Rodolfo Lima <rodolfo at rodsoft dot org>
- To: libstdc++ at gcc dot gnu dot org
- Date: Fri, 05 Jun 2009 08:45:26 -0300
- Subject: std::function with std::unique_ptr argument
Hi, I'm trying to use a std::function with std::unique_ptr arguments but
the std::function invocation ends up using std::unique_ptr copy ctor,
which is private/deleted.
Since std::function is a forward call wrapper, its operator() should
have forwarded properly its arguments to the wrapped function, but
M_invoker(_M_functor, __args...);
and
(*_Base::_M_get_pointer(__functor))(__args...);
doesn't seem to do that. IMHO it should be
_M_invoker(_M_functor, std::forward<_ArgTypes>(__args)...);
(*_Base::_M_get_pointer(__functor))(std::forward<_ArgTypes>(__args)...);
Any objections?
Regards,
Rodolfo Lima