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Re: Miscompilation of remainder expressions
Andrew Haley <aph@redhat.com> writes:
| Paolo Carlini writes:
| > Andrew Haley wrote:
| >
| > > > Ok, I believe you. However, isn't true that, in general, because the
| > > > sign of the result is implementation defined,
| > >
| > >The sign of the result of % is no longer (since C99) implementation-
| > >defined.
| > >
| > >
| > I see. However, by default, I'm always talking about C++03...
|
| I just had a look at that, and it seems that they haven't yet adopted
| the tightening-up of the langauge used by C. However, the footnote
| says:
|
| "74) According to work underway toward the revision of ISO C, the
| preferred algorithm for integer division follows the rules defined in
| the ISO Fortran standard, ISO/IEC 1539:1991, in which the quotient is
| always rounded toward zero."
|
| It would be a very brave developer who chose to do anything different.
Then, it seems we have brave GCC developers :-)
-- Gaby