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Re: Miscompilation of remainder expressions


Andrew Haley <aph@redhat.com> writes:

| Paolo Carlini writes:
|  > Andrew Haley wrote:
|  > 
|  > > > Ok, I believe you. However, isn't true that, in general, because the 
|  > > > sign of the result is implementation defined,
|  > >
|  > >The sign of the result of % is no longer (since C99) implementation-
|  > >defined.
|  > >  
|  > >
|  > I see. However, by default, I'm always talking about C++03...
| 
| I just had a look at that, and it seems that they haven't yet adopted
| the tightening-up of the langauge used by C.  However, the footnote
| says:
| 
| "74) According to work underway toward the revision of ISO C, the
| preferred algorithm for integer division follows the rules defined in
| the ISO Fortran standard, ISO/IEC 1539:1991, in which the quotient is
| always rounded toward zero."
| 
| It would be a very brave developer who chose to do anything different.

Then, it seems we have brave GCC developers :-)

-- Gaby


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