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Re: __builtin_cpow((0,0),(0,0))
Vincent Lefevre <vincent+gcc@vinc17.org> writes:
| On 2005-03-10 15:54:03 +0100, Gabriel Dos Reis wrote:
| > The C standard is not the holy bible and certainly does not define
| > everything. We're talking about compiler construction, here.
|
| This isn't just compiler construction. __builtin_cpow is equivalent
| to the C99 cpow (as said in gcc/doc/extend.texi), and the end-user
| is concerned by the C99 cpow.
|
| > | I disagree. One can mathematically define 0^0 as 1. One often does
| > | this.
| >
| > what you do is to set a local convention regardless of all
| > mathematical absurdities you run into. That is very different from
| > having 0^0 mathematically defined. I would have expected that the math
| > courses you took at ENS Lyon mentioned that.
|
| This is not a local convention. You probably have never seen a
| polynomial expression written like this: P(x) = \sum a_i x^i...
You probably noticed that in the polynomial expansion, you are using
an integer power -- which everybody agrees on yield 1 at the limit.
I'm tlaking about 0^0, when you look at the limit of function x^y
-- which is closer to cpow() tgan powi(). Did you miss that?
-- Gaby
- References:
- Re: __builtin_cpow((0,0),(0,0))
- Re: __builtin_cpow((0,0),(0,0))
- Re: __builtin_cpow((0,0),(0,0))
- Re: __builtin_cpow((0,0),(0,0))
- Re: __builtin_cpow((0,0),(0,0))
- Re: __builtin_cpow((0,0),(0,0))
- Re: __builtin_cpow((0,0),(0,0))
- Re: __builtin_cpow((0,0),(0,0))
- Re: __builtin_cpow((0,0),(0,0))
- Re: __builtin_cpow((0,0),(0,0))
- Re: __builtin_cpow((0,0),(0,0))