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Re: What happens with __attribute__((vector_size(8))) short a = {1, -1};?
>>>>> "Kazu" == Kazu Hirata <kazu@cs.umass.edu> writes:
> Hi Andrew,
>> > When the vector size and the amount of initialization do not match like
>> >
>> > __attribute__((vector_size(8))) short a = {1, -1};
>> >
>> > what is supposed to happen? Is the initialization assumed to be like
>> > so?
>> >
>>
>> This one, just like structs work:
>> > {1, -1, 0, 0}
It's supposed to initialize the non existing elements to zero.
I just tried it and it seems like it's horribly broken though.
I'm getting:
(const_vector:V2SI [
(const_int 1 [0x1])
(nil)
])
...for a partial initialization of a V2SI value, which is completely bogus.
> Thank you for a quick reply. Do you happen to know where this
> assumption is implemented? I am in the middle of debugging the
> failure of compile/20000804-1.c on H8.
This assumption should have been implemented in
const_vector_from_tree().
I'll take a look.