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Re: How to just print the output for -H without output anything else?

From: Alexander Monakov <amonakov at ispras dot ru>
To: Xi Ruoyao <xry111 at mengyan1223 dot wang>
Cc: Peng Yu <pengyu dot ut at gmail dot com>, "gcc-help at gcc dot gnu dot org" <gcc-help at gcc dot gnu dot org>
Date: Fri, 4 Jan 2019 11:42:14 +0300 (MSK)
Subject: Re: How to just print the output for -H without output anything else?
References: <CABrM6wmt4TTht9H41Ae-PsOcDHfevrm4GaddRJfhy0m6enBTcA@mail.gmail.com> <2e59952e46ea64375f74fae9e2f26647a16ab126.camel@mengyan1223.wang> <CABrM6w=BVZR4bTVJ1tNW9GUiafpOEyL-zi4yBemRQKhywBoZbw@mail.gmail.com> <d9f95bc4c144ea1cc80ac72b7ad74ade7af91134.camel@mengyan1223.wang>

On Fri, 4 Jan 2019, Xi Ruoyao wrote:

> On 2019-01-03 21:18 -0600, Peng Yu wrote:
> > > A "-c" option would work.
> > 
> > This still generates the .o file. Is there an option that disable all
> > the side effect but just print the header info as -H?
> 
> Maybe "-E -o /dev/null"?  Use "-E" instead of "-c" so the compiler and
> assembler will not run, and "-o /dev/null" to throw the result
> (preprocessed code).

There's also -fsyntax-only, but it does more work compared to -E -o/dev/null.

Alexander

References:
- How to just print the output for -H without output anything else?
  - From: Peng Yu
- Re: How to just print the output for -H without output anything else?
  - From: Xi Ruoyao
- Re: How to just print the output for -H without output anything else?
  - From: Peng Yu
- Re: How to just print the output for -H without output anything else?
  - From: Xi Ruoyao

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