Problem with 'struct timespec' and C99 standard

[npak at ispras dot ru (Nickolay Pakoulin)]

Hello all!

I can not compile a program with 'struct timespec' when gcc is instructed to
follow C99 standard.

OS:  RedHat 9 Cyrillic Edition
GCC:  3.2.2 and 3.3.2

Example:  let's put the following lines in file t.c

#include <time.h>
struct timespec t;

Then compile it:

$ gcc -c t.c

Works fine.

$ gcc -std=c99 -c t.c
t.c:3: storage size of `t' isn't known

BUT:
$ gcc -std=gnu99 -c t.c

works!

I tried Intel compiler and it compiled successfully:
$icc -std=c99 -c t.c

struct timespec is defined in <time.h> as:
-------------------------------------------------------------------------------
#if !defined __timespec_defined &&				\
    ((defined _TIME_H &&					\
      (defined __USE_POSIX199309 || defined __USE_MISC)) ||	\
      defined __need_timespec)
# define __timespec_defined	1

/* POSIX.1b structure for a time value.  This is like a `struct timeval' but
   has nanoseconds instead of microseconds.  */
struct timespec
  {
    __time_t tv_sec;		/* Seconds.  */
    long int tv_nsec;		/* Nanoseconds.  */
  };

#endif /* timespec not defined and <time.h> or need timespec.  */
#undef	__need_timespec
-------------------------------------------------------------------------------
The problem seems to be with __USE_POSIX199309: gcc does not define it when
-std=c99 is set.  Is a gcc feature that when it follows C99 it ignores
POSIX.1b?

Nick.

PS:  Please Cc: me , i am not subscribed to the list.