Re: Initialization of nested flexible array members

[Burak Serdar <bserdar at eos dot ncsu dot edu>]

This is a hack, but you may give it a try:

typedef struct
{
    char a;
    char b;
    int flexo[0];
} EnclosedStruct;

typedef struct
{
    int a;
    int b;
    EnclosedStruct s;
    int flexo[];
} MyStruct;

MyStruct toto = { 10, 20, { 'a', 'b'},{ 0, 1, 2, 3 }  };
int main(int argc, char * argv[])
{
    int i;
    for(i=0;i<4;i++)
      printf("%d\n",toto.s.flexo[i]);
}



Alexandre Courbot wrote:

> > Declare your stretchy-buffered struct this way:
> >
> > typedef struct
> > {
> >    char a;
> >    char b;
> >    int flexo[1024];
> > } EnclosedStruct;
> >
> > Instead of "1024", use whatever largest possible size the struct could
> > conceivably need to accommodate.
>
>
> This is unfortunately not an option, since the code is designed to run on 
> constraint embedded targets with 1K RAM at best... :)
>
> Alex.