[Bug fortran/58620] New: [OOP] Defined assignment not called for TYPE when the type's extension is used

["burnus at gcc dot gnu.org" <gcc-bugzilla at gcc dot gnu dot org>]

http://gcc.gnu.org/bugzilla/show_bug.cgi?id=58620

            Bug ID: 58620
           Summary: [OOP] Defined assignment not called for TYPE when the
                    type's extension is used
           Product: gcc
           Version: 4.9.0
            Status: UNCONFIRMED
          Keywords: wrong-code
          Severity: normal
          Priority: P3
         Component: fortran
          Assignee: unassigned at gcc dot gnu.org
          Reporter: burnus at gcc dot gnu.org

Follow up to PR58469

The code below prints "42" as the defined assignment "assign0" isn't called for
"foo". If one uses "type(component)" instead of "type(comp0)" for "foo", one
gets the expected output: "20".

See also https://groups.google.com/forum/#!topic/comp.lang.fortran/6cW1K0Zj1gU

pgf95 and ifort ICEs for the code; using crayftn one gets the same result as
with gfortran - namely "20".

module m0
  implicit none
  type :: component
    integer :: i = 42
  contains
    procedure :: assign0
    generic :: assignment(=) => assign0
  end type
  type, extends(component) :: comp2
    real :: aa
  end type comp2
  type parent
    type(comp2) :: foo
  end type
contains
  elemental subroutine assign0(lhs,rhs)
    class(component), intent(INout) :: lhs
    class(component), intent(in) :: rhs
    lhs%i = 20
  end subroutine
end module

program main
  use m0
  implicit none
  type(parent), allocatable :: left
  type(parent) :: right
  left = right
  print *, left%foo
  if (left%foo%i /= 20) call abort()
end