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[Bug lto/49703] New: -flto makes stack executable by default
- From: "marcus at jet dot franken.de" <gcc-bugzilla at gcc dot gnu dot org>
- To: gcc-bugs at gcc dot gnu dot org
- Date: Mon, 11 Jul 2011 11:59:38 +0000
- Subject: [Bug lto/49703] New: -flto makes stack executable by default
- Auto-submitted: auto-generated
http://gcc.gnu.org/bugzilla/show_bug.cgi?id=49703
Summary: -flto makes stack executable by default
Product: gcc
Version: 4.6.1
Status: UNCONFIRMED
Severity: critical
Priority: P3
Component: lto
AssignedTo: unassigned@gcc.gnu.org
ReportedBy: marcus@jet.franken.de
$ cat xx.c
#include <stdio.h>
int main(int argc, char **argv) {
printf("Hallo\n");
return 0;
}
$ gcc -O2 -o xx xx.c
$ readelf -a xx|grep STACK
GNU_STACK 0x000000 0x00000000 0x00000000 0x00000 0x00000 RW 0x4
$ gcc -flto -O2 -o xx xx.c
$ readelf -a xx|grep STACK
GNU_STACK 0x000000 0x00000000 0x00000000 0x00000 0x00000 RWE 0x4
-flto should not create executable stacks.