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[Bug debug/41097] Inlined variable debug location disappears when ptr type
- From: "mark at gcc dot gnu dot org" <gcc-bugzilla at gcc dot gnu dot org>
- To: gcc-bugs at gcc dot gnu dot org
- Date: 18 Aug 2009 08:11:45 -0000
- Subject: [Bug debug/41097] Inlined variable debug location disappears when ptr type
- References: <bug-41097-3639@http.gcc.gnu.org/bugzilla/>
- Reply-to: gcc-bugzilla at gcc dot gnu dot org
------- Comment #2 from mark at gcc dot gnu dot org 2009-08-18 08:11 -------
(In reply to comment #1)
> Wait a second are you saying:
> volatile char * p_name
>
> and p_name disappears?
> Well that is because p_name is no longer volatile but what it points to is.
Well, obvious p_name still is there, since it will be put in a register to feed
into the asm statement. But the debuginfo location for it is missing.
> I don't think this is a bug in GCC but rather a misunderstanding on how
> qualifiers apply to types.
>
> If you use a typedef for char*, does it disappear?
You are right, I misunderstood how the volatile qualifier "attached" to the
type. Using:
typedef char * char_ptr;
volatile char_ptr p_name = (char_ptr) name;
Does what I want. Thanks. That will allow me to write a workaround for what I
am seeing using typedef typeof(arg).
I am not sure this means the bug is really not there, because I am still a
little surprised (confused?) the location expression goes missing in the
original (and I assume the variable isn't actually fully optimized away). But
since I now have a workaround for that I am already happy. Thanks.
--
http://gcc.gnu.org/bugzilla/show_bug.cgi?id=41097