[Bug c++/36805] New: compilation fails when pointer to template-functions are returned by ?-operator

["rbuergel at web dot de" <gcc-bugzilla at gcc dot gnu dot org>]

The following program fails to compile:

template<typename T> void f()
{}

void g1() {}
void g2() {}

typedef void(*ptrType)();

int main(int argc, char** argv)
{
        ptrType p = argc == 1 ? &f<char> : &f<int>; //<-- error
        ptrType p2 = argc == 1 ? &g1 : &g2;

        ptrType p1;
        if (argc== 1)
                p1 = &f<char>;
        else
                p1 = &f<int>;
}

fptr.cpp:11: error: address of overloaded function with no contextual type
information

As f<char> and f<int> are the same pointer-type, this shouldn't fail. It
doesn't fail for non-template-functions and it aslo doesn't fail if an
if/else-clause is used.


tried with gcc-4.3.1, 4.2.4 and 4.1.2 on x86_64 and 4.2.3 on powerpc-uclibc


-- 
           Summary: compilation fails when pointer to template-functions are
                    returned by ?-operator
           Product: gcc
           Version: 4.2.3
            Status: UNCONFIRMED
          Severity: normal
          Priority: P3
         Component: c++
        AssignedTo: unassigned at gcc dot gnu dot org
        ReportedBy: rbuergel at web dot de


http://gcc.gnu.org/bugzilla/show_bug.cgi?id=36805