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[Bug c++/21672] Loses temporary in complex expression


------- Additional Comments From pinskia at gcc dot gnu dot org  2005-05-19 23:19 -------
(In reply to comment #4)
> but apparently the warning logic overlooks the same problem when returning
> arguments.

Actually it cannot know and here is why,
take the following example:
template<class T> const
 T& operator |(T t1, const T& t2) { return t1 |= t2; }

struct f{ f &operator|=(const f&);};
f i;
f j;

f h = i | j;

We call |= which it self returns a reference so there is no way to the compiler to know it is actually 
returning a local variable or not.

-- 
           What    |Removed                     |Added
----------------------------------------------------------------------------
             Status|UNCONFIRMED                 |RESOLVED
         Resolution|                            |INVALID


http://gcc.gnu.org/bugzilla/show_bug.cgi?id=21672


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