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[Bug c++/20976] when terminate is called, stack is not unwinded


------- Additional Comments From pinskia at gcc dot gnu dot org  2005-04-12 19:23 -------
Ok, this is just implemenation defined behavior.
see 15.3 P 9:
If no matching handler is found in a program, the function terminate() is called; whether or not the 
stack is unwound before this call to terminate() is implemenation-defined (15.5.1)

So we define it as not unwinding but we don't document this.

Confirmed for documentation.

-- 
           What    |Removed                     |Added
----------------------------------------------------------------------------
             Status|UNCONFIRMED                 |NEW
     Ever Confirmed|                            |1
           Keywords|                            |documentation
   Last reconfirmed|0000-00-00 00:00:00         |2005-04-12 19:23:16
               date|                            |
            Summary|when exceptions are not     |when terminate is called,
                   |caught, destructors of local|stack is not unwinded
                   |vars are not executed       |


http://gcc.gnu.org/bugzilla/show_bug.cgi?id=20976


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