[Bug c++/11893] stdcall pointers to member-functions handled wrong

["boaz at hishome dot net" <gcc-bugzilla at gcc dot gnu dot org>]

PLEASE REPLY TO gcc-bugzilla@gcc.gnu.org ONLY, *NOT* gcc-bugs@gcc.gnu.org.

http://gcc.gnu.org/bugzilla/show_bug.cgi?id=11893



------- Additional Comments From boaz at hishome dot net  2003-08-13 11:48 -------
I have found a nice Work around that also introduces a very good code practice
Here is the code:

< c++ code >

#define __stdcall __attribute__((__stdcall__))
class AFoo
{
public:
  __stdcall  void foo(int i ,int ii ,int iii) ;
} ;

__stdcall
void AFoo::foo(int i ,int ii ,int iii)
{
    return ;
}

int main()
{
  AFoo afoo ;

  // now here is the nice thing Note the use of typeof() operator
  typedef  typeof(&AFoo::foo) Afoo_func ;

  Afoo_func func = &AFoo::foo ;

  for(int i=0 ; i < 0x8000000 ;i++)
     (afoo.*func )(1,2,3) ; // the code gets to be right this time

  return 0 ;
}
< c++ code/>

Well there it is. I am not sure how to make existing (Windows) code compile but
new code can use this syntax to have pointers to __stdcall member functions work
right. (I think that the fact this works shows that the problem is in the parser
and not the Generating of code.)
I like this syntax better than the classical one because, in evolving code,
typedef of functions-pointers do not have to change, when a decision is made to
change the functions prototype.

I hope this is any help
Free Life
Boaz