Re: too many warnings

[Martin von Loewis <martin at mira dot isdn dot cs dot tu-berlin dot de>]

> The warning is correct, your code is incorrect; you failed to
> indicate, that the numeric literal is 'unsigned' by appending a 'U'.

To further support this claim, I quote from the C++ standard,
[lex.icon]/2

>> The type of an integer literal depends on its form, value, and
>> suffix. If it is decimal and has no suffix, it has the first of
>> these types in which its value can be represented: int, long int;
>> if the value cannot be repre­sented as a long int, the behavior is
>> undefined.

Since long can represent 2**31 at most on the architecture you are
using, the behaviour of your program is undefined (I assume a similar
statement holds for in standard C).

g++ accepts this program, anyway; it supports representing your number
as an unsigned int. Since this is an extension, it must be diagnosed
by a standards compliant compiler.

As Manfred points out, you can fix it by appending 'U'. Alternatively,
could could write it in hex or oct.

Hope this helps,
Martin