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Re: std::max: if versus ?:
On Sun, Sep 23, 2012 at 12:06 PM, Marc Glisse <marc.glisse@inria.fr> wrote:
> On Sun, 23 Sep 2012, Gabriel Dos Reis wrote:
>
>> On Sun, Sep 23, 2012 at 10:09 AM, Marc Glisse <marc.glisse@inria.fr>
>> wrote:
>>
>>> Then that may mean no std::max for vectors, at least until someone makes
>>> the
>>> inner type and size of vectors deducible (that would make the vector
>>> version
>>> of max more specialized than the generic one and allow overloads without
>>> touching the generic function). Which isn't that bad, people are big
>>> enough
>>> to write (x<y)?y:x themselves...
>>
>>
>> I do not understand why you can't have a syntax such as __vector<T,N>
>> those extensions. If that syntax isn't there, you should consider adding
>> it. It is a natural thing to have.
>
>
> The syntax exists (though it is ugly): T __attribute__((vector_size(N))).
that is why I suggested __vector<T,N>.
> What doesn't work currently is that T and N are not deducible, in a template
> context. One possibility would be to make them deducible
Yes. That is a more scalable solution, IMO.
> (sounds like duplicating a bit of template machinery).
Why?
-- Gaby