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Re: About std::vector::resize().

Carlo Wood wrote:

On Tue, May 25, 2004 at 01:05:04PM -0600, Martin Sebor wrote:

Theodore Papadopoulo wrote:
The code below must not abort for any (n > 0) but if resize()
constructed a new vector and swapped *this for it, it would.

   std::vector<T> v;
   v.resize (1);
   v.reserve (n);
   T *p = &v [0];
   v.resize (n);   // must not reallocate



Because the (reserved) "size" is already n there is no need
for reallocation - so the mentioned algorithm will not
be used.

Ah. Sorry for the misunderstanding.

FYI, the "reserved size" of a vector is known as its capacity :)

Martin

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