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Keith> + bytes[i++] = (byte) ((length >>> 24) & 0xff);
These don't need the '& 0xff' as the cast to byte does that implicitly. But if you want to keep this for extra clarity, I won't complain.
And >>> fills with zero always which is unlike >> which fills with the sign bit (>>> is like unsigned >> in C/C++).
Thanks, Andrew Pinski
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