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GCC 6.2.0 : What does the undocumented -r option ?
- From: Emmanuel Charpentier <emm dot charpentier at free dot fr>
- To: gcc at gcc dot gnu dot org
- Date: Mon, 07 Nov 2016 19:34:01 +0100
- Subject: GCC 6.2.0 : What does the undocumented -r option ?
- Authentication-results: sourceware.org; auth=none
- Reply-to: emm dot charpentier at free dot fr, gcc at gcc dot gnu dot org
The Sage project (http://www.sagemath.org) has recently hit an
interesting snag : its developers using Debian testing began to
encounter difficulties compiling the flint package (http://groups.googl
e.co.uk/group/flint-devel) with gcc 2.6.0.
One of us found (see https://groups.google.com/d/msg/sage-devel/TduebNo
ZuBE/sEULolL0BQAJ) that this was bound to a conflict between the -pie
option (now default) and an undocumented -r option.
We would like to know what is this -r option, what it does and why it
PS Could you Cc me of your answers ? I'm not usually following this
list. (Reply-to suitably positioned).