Re: GIMPLE Question

[Kyle Girard <kyle at kdmanalytics dot com>]

>   That *is* the content of the bar method.  What exactly do you expect to see
> happening when you assign a class with no members?  There's nothing to do!


I was hoping to see the assignment.  My example might have been a little
too simple.  Here's a slightly more complex example:

foo.hh

class A
{
public:
   void yay(){};
};

class foo
{
  A a;
public:
    void bar(A & aa);
    void wik();
};


foo.cc


#include "foo.hh"

void foo::bar(A & aa)
{
  a = aa;
}

void foo::wik()
{
  a.yay();
}


foo.cc.004t.gimple


void foo::wik() (struct foo * const this)
{
  struct A * D.1731;

  D.1731 = &this->a;
  A::yay (D.1731);
}


void A::yay() (struct A * const this)
{
  GIMPLE_NOP
}


void foo::bar(A&) (struct foo * const this, struct A & aa)
{
  GIMPLE_NOP
}


Looking at the gimple output there is no way to see that 'a' was
assigned in bar().  So that it can be used in wik().  Am I
misunderstanding something shouldn't there be a way to see the
assignment in bar?  Do I have to parse the expression statement or are
things already optimized away and there is no way to get the information
that I seek.


Cheers,

Kyle