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Re: Preparsing sprintf format strings

From: Joe Buck <Joe dot Buck at synopsys dot COM>
To: "Kaveh R. GHAZI" <ghazi at caip dot rutgers dot edu>
Cc: Heikki Linnakangas <heikki at enterprisedb dot com>, gcc at gcc dot gnu dot org
Date: Wed, 10 Oct 2007 08:16:10 -0700
Subject: Re: Preparsing sprintf format strings
References: <470A2788.8080408@enterprisedb.com> <Pine.GSO.4.58.0710091648140.1868@caipclassic.rutgers.edu>

On Wed, Oct 10, 2007 at 12:12:25AM -0400, Kaveh R. GHAZI wrote:
> One simplification I don't believe we do yet, that should always be a win,
> is turning:   sprintf (foo, "%c", bar);   into:    *foo = bar;

You need the null terminator: foo[0] = bar; foo[1] = 0;
But these things are rarely going to be a huge win, and I get
the impression that competing compiler developers only do them
when they help with standard benchmarks.

Follow-Ups:
- Re: Preparsing sprintf format strings
  - From: Kaveh R. GHAZI

References:
- Preparsing sprintf format strings
  - From: Heikki Linnakangas
- Re: Preparsing sprintf format strings
  - From: Kaveh R. GHAZI

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