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Herman Geza <hg211@hszk.bme.hu> writes:
[...]
What is the correct way to do this:
void setNaN(float &v) { reinterpret_cast<int&>(v) = 0x7f800001; }
without a type-prunning warning? I cannot use the union trick here
Why? Won't the following work?
void setNaN(float &v) { union { float f; int i; } t; t.i = 0x7f800001; v = t.f; }
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