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Re: Miscompilation of remainder expressions
On Tue, 16 Jan 2007, Joe Buck wrote:
| On Tue, Jan 16, 2007 at 12:05:12PM -0600, Gabriel Dos Reis wrote:
| > By definition, the absolute value of "a % b" is always less than the
| > absolute value of b. Consequently, "a % b" is always defined.
| Nitpick: for nonzero b.
yes, I assumed that -- since the standard says that the result is
undefined when b is zero. I should have repeated that assumption.