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Re: Miscompilation of remainder expressions
Paolo Carlini writes:
> Andrew Haley wrote:
>
> > > Ok, I believe you. However, isn't true that, in general, because the
> > > sign of the result is implementation defined,
> >
> >The sign of the result of % is no longer (since C99) implementation-
> >defined.
> >
> >
> I see. However, by default, I'm always talking about C++03...
I just had a look at that, and it seems that they haven't yet adopted
the tightening-up of the langauge used by C. However, the footnote
says:
"74) According to work underway toward the revision of ISO C, the
preferred algorithm for integer division follows the rules defined in
the ISO Fortran standard, ISO/IEC 1539:1991, in which the quotient is
always rounded toward zero."
It would be a very brave developer who chose to do anything different.
Andrew.