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Re: Constant propagation and address arithmetic

On Sun, May 08, 2005 at 10:06:04PM +0200, Steven Bosscher wrote:
> A test case that shows what is going on is this:
> 
> extern char *x;
> void
> foo (char *a, char *b)
> {
>   if (!x)
>     x = a;
>   else
>     x = b;
> }

This test case doesn't show anything.  .04.cse merges all the high parts
of x, and none of the gcse passes do anything.  Unless you're working with
some modified tree?



r~
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