How to get MIN_EXPR without using deprecated min operator

["Michael Cieslinski" <micis at gmx dot de>]

Consider the following short program:

    #include <algorithm>
    
    void Tst1(short* __restrict__ SrcP, short* __restrict__ MinP, int Len)
    {
        for (int x=0; x<Len; x++)
            MinP[x] = SrcP[x] <? MinP[x];
    }
    
    void Tst2(short* __restrict__ SrcP, short* __restrict__ MinP, int Len)
    {
        for (int x=0; x<Len; x++)
            MinP[x] = std::min(SrcP[x], MinP[x]);
    }


If I compile it with
    gcc41 -O2 -ftree-vectorize -ftree-vectorizer-verbose=5
function Tst1 gets vectorized but Tst2 not.

The reason for this is <? results in a MIN_EXPR while std::min generates a
conditional code.
My question is, how can I get a MIN_EXPR without using the deprecated min <?
operator?

Michael Cieslinski