This is the mail archive of the
gcc@gcc.gnu.org
mailing list for the GCC project.
Re: __builtin_cpow((0,0),(0,0))
Hi again,
a small proof.
if A and X are real numbers and A>0 then
A^X := exp(X*ln(A)) (Definition in analytical mathematics).
0^0 = lim A->0, A>0 (exp(0*ln(A)) = 1 if exp(X*ln(A)) is continual continued
The complex case can be derived from this (0^(0+ib) = 0^0*0^ib = 1 =
0^a*0^(i*0) ).
Well, i know only the german mathematical expressions, so maybe the
translations to english are not accurate, sorry for this :)
cu, Ronny
- References:
- __builtin_cpow((0,0),(0,0))
- Re: __builtin_cpow((0,0),(0,0))
- Re: __builtin_cpow((0,0),(0,0))
- Re: __builtin_cpow((0,0),(0,0))
- Re: __builtin_cpow((0,0),(0,0))
- Re: __builtin_cpow((0,0),(0,0))
- Re: __builtin_cpow((0,0),(0,0))
- Re: __builtin_cpow((0,0),(0,0))