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Re: Local binding DECLs



On Monday, May 12, 2003, at 02:44 AM, Stephen Biggs wrote:


On Mon, 2003-05-12 at 04:13, Richard Henderson wrote:
On Sun, May 11, 2003 at 10:04:20AM +0300, Stephen Biggs wrote:
Ok... is there ANY way to find out if the FUNCTION_DECL I am handed at
any time (preferably in ENCODE_SECTION) is declared in a function block
as opposed to globally?

*Declared*? I.e. to distinguish


	extern void foo();
	void bar() { foo(); }

from

	void bar() {
	  extern void foo();
	  foo();
	}

Absolutely not. That question doesn't even make sense.


r~


Sure it does, if you have, for example:

void bar() {
  static void foo();
  foo();
}

void bar1() {
  static int foo();
  foo();
}

void bar2() {
  static int foo(int);
  int a = foo(3);
}
foo() {}

This compiles.

I see nothing that gives me the ability to know that any particular DECL
is declared inside a particular function.




Errr, won't DECL_CONTEXT do what you want?
From tree.h:
/* For FIELD_DECLs, this is the
RECORD_TYPE, UNION_TYPE, or QUAL_UNION_TYPE node that the field is
a member of. For VAR_DECL, PARM_DECL, FUNCTION_DECL, LABEL_DECL,
and CONST_DECL nodes, this points to either the FUNCTION_DECL for the
containing function, the RECORD_TYPE or UNION_TYPE for the containing
type, or NULL_TREE if the given decl has "file scope". */
#define DECL_CONTEXT(NODE) (DECL_CHECK (NODE)->decl.context)



DECL_CONTEXT on a contained function_decl should give you the containing function_decl (or NULL_TREE if it's not contained/is file scope), as the comment says.
Does it not work?
I haven't really been following till now.
--Dan



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