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Re: multilib support in libiberty
OK, thanks. I've been looking at it too. The host side compilation of
libiberty is working OK. The problem is that the all target in the
Makefile.in has $(TARGETLIB) in there which causes it to always compile
in the directory. Unfortunately for me, I have setup my multilibs so
that there is no valid default.
On Mon, 2002-08-12 at 16:30, Michael S. Zick wrote:
> On Monday 12 August 2002 05:38 pm, Sean McNeil wrote:
> > Hello everyone,
> > but then it goes into the main libiberty directory and starts to compile
> > directly in there instead of the subdir MIPS64gnule as it should:
> During my battles last week with understanding the gCC makefile, I noticed
> that it tries to build libiberty for nearly any possible command.
> Sorry, I don't have a fix (yet) - but the problem is more general. (Usually,
> the "build" machine compiler will need libiberty; and the "host" machine
> perhaps; and the "target" machine maybe.)
> For your example (a simple cross compiler "Build" == "Host", "Target" ==
> different) - What you see may be the building of libiberty for the Build/Host