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Re: Reassociation




On Sun, 20 Dec 1998, Richard Henderson wrote:

> No, because that looses on ((a*b)*c)*d. 
> 
> We must add something to the tree.  There is no way to determine
> where the parentheses were.

Yes, I see you're right.  No way to tell whether the source program
had those particular parentheses or omitted them.  They generate the
same rtl as a*b*c*d.


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