Re: quick question

[Xiaomao Xiao <xiao at cmold dot com>]

>>>>> "Martin" == Martin von Loewis <martin@mira.isdn.cs.tu-berlin.de> writes:

>> When I used gcc to compile my codes, I found that the compiler didn't examine
>> all my codes.  It seemed that it only check those functions in classes which
>> I actually used in an application.

FMartin> No, the compiler examines all source code it compiles. Can you provide
FMartin> a specific example?

FMartin> Martin

Here is a simple piece of code:

template <class T>
void test1(T v1, T v2)
{
  v = v1;
}

int main(int, char**)
{
  float a;

  a = 0.1f;
  test1(a, 0.1f);

  return (0);
}

You notice the variable v in the template function test1() is undeclared.  In the
main() function, if I comment out the line calling test1(), the compiler gives
no complains and generate an executable.  If we include the line, then the
compiler is able to pick out the error:

test.cpp: In function `void test1(float, float)':
test.cpp:4: `v' undeclared (first use this function)
test.cpp:4: (Each undeclared identifier is reported only once
test.cpp:4: for each function it appears in.)

Is there an option which I can use to force the compiler to examine all the
codes?

-- 

Xiaomao

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