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LWG 2931 suggests a new overload of std::next for the default n==1 case, because it can be simpler for some random access iterators to do ++i than i += 1, e.g. for std::deque::iterator. I've suggested we close that issue as NAD, because we don't need a new overload to do that, and here's the proof. This performs the same optimisation when the argument to __advance<RandomAccessIterator> is known at compile-time to be +1 or -1, as is the case when called from std::next(i) or std::prev(i). This makes the generated assembly for std::next<std::deque<T,A>::iterator>(i) quite a lot shorter. In practice we probably don't need the optimisation in std::advance, only in std::next and std::prev, because it would be very unusual to call std::advance(i, 1) or std::advance(i, -1) when you could just do ++i or --i. But doing it here means we handle the std::next/std::prev cases, and std::advance, and any unusual cases like std::next(i, -1). * include/bits/stl_iterator_base_funcs.h (__advance<_RandomAccessIterator, _Distance>): Optimize for next/prev cases where incrementing or decrementing a single step. Tested powerpc64le-linux, committed to trunk.
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