This is the mail archive of the
mailing list for the GCC project.
Re: Volatile MEMs in statement expressions and functions inlinedastrees
- From: Paul Schlie <schlie at mediaone dot net>
- To: Jason Merrill <jason at redhat dot com>
- Cc: Linus Torvalds <torvalds at transmeta dot com>, Alexandre Oliva <aoliva at redhat dot com>, Richard Henderson <rth at redhat dot com>, <gdr at codesourcery dot com>, <gcc-patches at gcc dot gnu dot org>
- Date: Sun, 16 Dec 2001 16:39:37 -0500
- Subject: Re: Volatile MEMs in statement expressions and functions inlinedastrees
(please see annotations below)
>>>>>> "Paul" == Paul Schlie <email@example.com> writes:
>>>>>>>> "Paul" == Paul Schlie <firstname.lastname@example.org> writes:
>>>> (tt)(lv = rv) :: (lv = ((lt)tmp = rv, (lt)tmp), (tt)((lt)tmp))
>>> Nope. If this was the case, then (x += y) += z would add z to some random
>> Would have expected it to unambiguously be equivalent to:
>> x = x + y, x = x + z;
> As would I. Actually, I should have said '(x = y) += z'; based on your
> transformation above, I would expect this to become
> tmp = y, x = tmp, tmp = tmp + z
> whereas it should be
> x = y, x = x + z
> or am I misinterpreting you?
In which case I would re-write it as:
x = y, x = x + z
:: x = (x = ((xt)tmp = y, (xt)tmp)), ((xt)tmp2 = x, (xt)tmp2)
+ ((xt)tmp3 = y, (xt)tmp3))
x = y + z
:: x = ((xt)tmp = y, (xt)tmp) + ((xt)temp2 = z, (xt)tmp2)
Depending on adherence to an abstract rule requiring correlation between
the number and sequence of explicit original coded references to a volatile
within an expression, to it's correspondingly more restrictive semantic
>> But in no case should the interpretation be ambiguous, some uniform rule
>> should be established.
>>>> And it is agreed that:
>>>> volatile q
>>>> (q = 10) == 10
>>> No, that's where I disagree.
>> It it being asserted that:
>> volatile q
>> (q = 10) == 10
>> is ambiguous, and therefore defined?
> I am asserting that in C++ the above is unambiguously equivalent to
> q = 10, q == 10
> and therefore the result of the comparison cannot be predicted.
Hence you are asserting that "(q = 10) == 10" may not be true, if q is