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Re: Problems with the way we calculate costs

> Date: Mon, 11 Sep 2000 10:15:25 +0100 (BST)
> From: Bernd Schmidt <>
> cc:
> On Mon, 11 Sep 2000, Geoff Keating wrote:
> > It'd probably be better if it worked like the original code; that is,
> > the cost of a non-fixed hard register is 2, compared to 1 for a
> > pseudo.  This ensures a pseudo gets preference, which would be the
> > usual case because such hard registers should be copied into pseudos
> > immediately after they appear.
> The original code mixed up these register pressure considerations with
> the calculation of the cost of an operation.  I still think this is a
> bad idea.  It also won't reliably prevent lifetimes of hard registers
> from being lenghtened (think of computing the cost of a shift of a
> hardreg as opposed to multiplication of a pseudo).

I don't mind hard register lifetimes being lengthened if it really
makes the program faster; what I was complaining about is when a
hardreg and a pseudo are equivalent and the hardreg gets preference.

[I claim, though, that in at least the rs6000 backend it will _always_
be true that a hard reg is either fixed or equivalent to a pseudo.]

Probably the macro to consider is SMALL_REGISTER_CLASSES.

- Geoffrey Keating <>

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