On Fri, 31 Aug 2018 at 21:15, lejeczek <peljasz@yahoo.co.uk> wrote:
On 31/08/18 19:56, Jonathan Wakely wrote:
On Fri, 31 Aug 2018 at 18:55, lejeczek via gcc-help
<gcc-help@gcc.gnu.org> wrote:
hi guys
I have cron which is supposed to update a few things which involves
compiler but it fails. I could find only one bit which is not there, but
which there for root when root does the same thing.
Cron does not seem to get COLLECT_LTO_WRAPPER declared. And that is on
one box where a sister box's cron gets it okey.
How to fix that? (I'm on Centos 7.5)
You haven't said what the problem is.
You need to tell us what you're trying to do and what the error you
get is. Just saying it "involves compiler but it fails" is not enough
for us to help.
could we just keep it simple for now?
I'm trying to.
When as root in bash session I do:
] gcc -v
Using built-in specs.
COLLECT_GCC=gcc
COLLECT_LTO_WRAPPER=/usr/libexec/gcc/x86_64-redhat-linux/4.8.5/lto-wrapper
Target: x86_64-redhat-linux
...
But when crond does the same then COLLECT_LTO_WRAPPER is not
there.
That suggests you're looking at two different 'gcc' executables.
Is it possible to fix that first?
You can't change that, it's baked in when GCC is built. It's not
something that "cron gets declared".
Why does it matter? Is the cron job trying to print the name of GCC's
LTO wrapper? Are using using LTO? If not, why do you think that's the
problem?
What are you actually trying to do that fails? Tell us that, instead
of what you think is wrong and needs to be fixed. That's an XY problem
(https://en.wikipedia.org/wiki/XY_problem).