This is the mail archive of the gcc-help@gcc.gnu.org mailing list for the GCC project.
| Index Nav: | [Date Index] [Subject Index] [Author Index] [Thread Index] | |
|---|---|---|
| Message Nav: | [Date Prev] [Date Next] | [Thread Prev] [Thread Next] |
| Other format: | [Raw text] | |
Dear Sirs,
I have wrote a simple program that assigns a complex number a number in the form of a + b*I
and when I print it the numbers I noticed loss of precision. It does not seem it is recognizing it as a double.
#include <stdio.h>
#include <math.h>
#include <complex.h>
int main (int argc, const char * argv[]) {
complex double y[1][1];
y[0][0] = (double) -0.107692307692308 + (double) 0.061538461538462*I;
printf("\n------------------- Complex Array Assignment ---------------------------------------------------\n");
printf("\n(%+10.15f,%+10.15f)", crealf(y[0][0]), cimagf(y[0][0]));
printf("\n");
printf("\n\n----------------------------------------------------------------------------------------------\n");
return 0;
}
This is what you will get:
------------------- Complex Array Assignment ---------------------------------------------------
(-0.107692308723927,+0.061538461595774)
----------------------------------------------------------------------------------------------
I have attached the file and my compiler is:
i686-apple-darwin10-gcc-4.2.1
-Amin Al-Juffali
ajuffali@mac.com
Attachment:
complexTest.c
Description: Binary data
| Index Nav: | [Date Index] [Subject Index] [Author Index] [Thread Index] | |
|---|---|---|
| Message Nav: | [Date Prev] [Date Next] | [Thread Prev] [Thread Next] |