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mismatched paramters in error messages are reported as expressions and not types
- From: KÅiÅtof Åelechovski <giecrilj at stegny dot 2a dot pl>
- To: gcc-help at gcc dot gnu dot org
- Date: Wed, 21 Sep 2011 13:08:14 +0200
- Subject: mismatched paramters in error messages are reported as expressions and not types
g++ (4.6) recently threw at me the following error message:
doit.cpp:290:129: error: no match for âoperator<<â in âstd::cout << boost::range::equal_range [with ForwardRange = boost::range_detail::transform_range<boost::value_factory<ls::file_rec<char>::as_char0>, std::vector<ls::file_rec<char> > >, Value = int, typename boost::range_iterator<const ForwardRange>::type = boost::transform_iterator<boost::value_factory<ls::file_rec<char>::as_char0>, __gnu_cxx::__normal_iterator<ls::file_rec<char>*, std::vector<ls::file_rec<char> > >, boost::use_default, boost::use_default>]((*(const boost::range_detail::transform_range<boost::value_factory<ls::file_rec<char>::as_char0>, std::vector<ls::file_rec<char> > >*)(& boost::range_detail::operator| [with InputRng = std::vector<ls::file_rec<char> >, UnaryFunction = boost::value_factory<ls::file_rec<char>::as_char0>]((* & lv_fr), (*(const boost::range_detail::transform_holder<boost::value_factory<ls::file_rec<char>::as_char0> >*)(& boost::adaptors::{anonymous}::transformed.boost::range_detail::forwarder<Holder>::operator() [with T = boost::value_factory<ls::file_rec<char>::as_char0>, Holder = boost::range_detail::transform_holder]((boost::value_factory<ls::file_rec<char>::as_char0>(), boost::value_factory<ls::file_rec<char>::as_char0>()))))))), (* &((int)a_n.std::basic_string<_CharT, _Traits, _Alloc>::operator[] [with _CharT = char, _Traits = std::char_traits<char>, _Alloc = std::allocator<char>, std::basic_string<_CharT, _Traits, _Alloc>::reference = char&, std::basic_string<_CharT, _Traits, _Alloc>::size_type = long unsigned int](0ul))))â
Am I suppposed to read and understand this? It is overwhelming.
The same message, somewhat split, is a bit more readable:
doit.cpp:290:129:
error: no match for âoperator<<â in â
std::cout <<
boost::range::equal_range
[with
ForwardRange = boost::range_detail::transform_range<boost::value_factory<ls::file_rec<char>::as_char0>, std::vector<ls::file_rec<char> > >,
Value = int,
typename boost::range_iterator<const ForwardRange>::type =
boost::transform_iterator<
boost::value_factory<ls::file_rec<char>::as_char0>, __gnu_cxx::__normal_iterator<ls::file_rec<char>*, std::vector<ls::file_rec<char> > >, boost::use_default, boost::use_default>]
(
(
*
(const boost::range_detail::transform_range<boost::value_factory<ls::file_rec<char>::as_char0>, std::vector<ls::file_rec<char> > >*)
(
& boost::range_detail::operator| [with InputRng = std::vector<ls::file_rec<char> >, UnaryFunction = boost::value_factory<ls::file_rec<char>::as_char0>]
(
(* & lv_fr),
(
*
(const boost::range_detail::transform_holder<boost::value_factory<ls::file_rec<char>::as_char0> >*)
(
&
boost::adaptors::{anonymous}::transformed.boost::range_detail::forwarder<Holder>::operator()
[with T = boost::value_factory<ls::file_rec<char>::as_char0>, Holder = boost::range_detail::transform_holder]
((boost::value_factory<ls::file_rec<char>::as_char0>(), boost::value_factory<ls::file_rec<char>::as_char0>()))))))),
(
*
&
(
(int)
a_n.
std::basic_string<_CharT, _Traits, _Alloc>::operator[]
[with
_CharT = char, _Traits = std::char_traits<char>, _Alloc = std::allocator<char>,
std::basic_string<_CharT, _Traits, _Alloc>::reference = char&, std::basic_string<_CharT, _Traits, _Alloc>::size_type = long unsigned int](0ul))))â
What we can see is that the error message does not tell me the types that do not match but the expressions that do not match, and while subexpressions are sometimes marked with types, the type of the mismatched argument is only mentioned in the following notes. I mean, is it really necessary to dump the whole expression instead of just reporting the failing argument types? Is there a switch to turn it off?
Chris