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Re: Passing an address to a #define in C

Hi Gus, 
This is because your code finally ends up with this expression:
(void*)ptr>>  4

and gcc doesn't allow the shift operation to be performed on pointer
types. A possible solution to your problem could be the following code:

For the sake of completeness, if you're wondering why gcc requires an integer type, please check the C standard:

6.5.7 Bitwise shift operators
[...]

Constraints
  Each of the operands shall have integer type.

Best regards,
Andre-Marcel

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