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Re: Needed help on compiler option


On 05/17/2011 11:48 AM, bhamidipati subrahmanyam wrote:

> Pls have a look at the following code snippet....
> 
> void test(int i)
> {
>     printf("i:%d\n",i);
> }
> 
> int main()
> {
>     char arr[100];
> 
>     arr[1] = 10;
> 
>     test(arr[1]);
> 
>     return 0;
> }
> 
> Logically, this code is working. But this simple concept resembles a
> real time problem,
> where the compiler should generate a warning when there is a type mismatch.

Where is the type mismatch?  All I see is the implicit widening argument
conversion described in 6.5.2.2 Para 7.  This doesn't alter the value,
so it's not flagged by -Wconversion.

Andrew.


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