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Re: map and virtual operator< for base class

I believe the second definition masks the first, rather than overriding the first, because the input is different:
const Base&
vs.
const Tst&

Bernd Prager wrote: 

class Base {
public:
virtual bool operator<(const Base& b) const;
...};

...

class Tst: public Base {
public:
bool operator<(const Tst& t) const; // less then


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