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Re: create an object with variable CLASS
You caused i open OOP in C++ book & start reading.My skill is python
programming & C.
But i have a question about previos source:
When i compile my source, i get seg fau, When i run it with gdb, i rcv
following message:
_IO_vfscanf () from /lib/i686/cmov/libc.so.6
Then i changed create_object to following code :
module_management* create_object(char * class_name){
if (c_find(class_name) == NULL){
if (strcmp (class_name,"mikrotik") == 0){
mikrotik *iu ;
return iu;//new mikrotik;
}//end of strcmp
}//end of c_find if block
exit(1);
}//end of func
/////////////////////////////////////
When i compile it, i use following error with GDB:
250 create_object("mikrotik")->printg();
Current language: auto
/////////////////////////////////////////////////////
I guess it return same Base object, because i tested with following
function:
cout <<typeid(create_object("mikrotik")).name() << endl;
and i see it printed type of Base classs of mikrotik.
Do you have any idea?
On Wed, 2009-10-28 at 03:11 +0330, Mohsen Pahlevanzadeh wrote:
> Oh, shit, Thank you Andrew & Axel.
> On Tue, 2009-10-27 at 11:34 +0000, Andrew Haley wrote:
> > Mohsen Pahlevanzadeh wrote:
> > > My main file:
> > > int main(){
> > > module_management *x;
> > > x.printg();
> > > }
> >
> > Well, that's not going to work, is it? x is a pointer, not
> > an object. You need
> >
> > x = create_object("mikrotik");
> > x->printg();
> >
> > Andrew.
>
>