c++: Function style initializer

[jorgesmbox-ml at yahoo dot es]

Hi,
I experienced something I consider strange: Let me try to explain by a simpe example:

Definitions:

class B;

class A {
A(B par=0);
}

Now, if I use:

A myA(myB); // assume myB is of type B

then I have an object of type A created, but if I do:

A myA();

Then no object of type A is created. I thought that because of the default value in the constructor, I could create myA
this way, but I get no error nor object. I was beaten by this last week, and it cost me many hours to debug. Am I missing something? Forgive me if the answer is trivial, I am not an expert in c++ and besides I started coding again after more than a year. Pointers are also appreciated, I have the latest Stroustrup's but I just started it and a search didn't answer this question.

jorges



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