Re: Can't generate a 'movd' instructuction

[James HAUXWELL <james dot hauxwell at st dot com>]

Ankit,

here is the objdump of the .o and it is definitely a movq instruction.

    765:       0f 6f c1                movq   %mm1,%mm0
    768:       0f 73 d0 20             psrlq  $0x20,%mm0
    76c:       0f fe c8                paddd  %mm0,%mm1
    76f:       0f 7f 4d e8             movq   %mm1,0xffffffe8(%ebp)
    773:       8b 45 e8                mov    0xffffffe8(%ebp),%eax

my compile options are -march=pentium4 -mfpmath=sse -msse2 -O3

I should have mentioned the version number I am on, so we can check if 
you are on a later version.

gcc (GCC) 3.4.1 (cygming special)
Copyright (C) 2004 Free Software Foundation, Inc.
This is free software; see the source for copying conditions.  There is NO
warranty; not even for MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE.

Jim

> hi
>
> --- James HAUXWELL <james.hauxwell@st.com> wrote: 
>  
>
> > Hi,
> >
> > I have a piece of code using mmx/sse intrinsics
> >
> >    ta = __builtin_ia32_pmaddwd(ia, one);
> >    tb = (v2si)__builtin_ia32_psrlq((di)ta, 32);
> >    dest.__v = __builtin_ia32_paddd(ta, tb);
> >    satd = dest.__a[0];
> >
> > At the phase where I move the bottom 32bits of the
> > mmx register to a 
> > normal register
> >    
>
> well i have a doubt in this i.e whether this is really
> happening or not. because i am also usign gcc compiler
> only and movd instrction works. if your things work
> let me also know about it
>
> thanks
>
> I should be able to use a movd
>  
>
> > instruction (according to 
> > intel documentation), but what ever I do I can't
> > generate one.  It is 
> > currently generating a movq to a memory loacation
> > and then doing a 
> > shorter load from the same location.
> >
> > should be something like.
> >
> >    ta = __builtin_ia32_pmaddwd(ia, one);
> >    tb = (v2si)__builtin_ia32_psrlq((di)ta, 32);
> >    satd = (int)__builtin_ia32_paddd(ta, tb);
> >
> > Is anyone familiar enough with intrinsics to know
> > why this doesn't work?
> >
> > Jim
> >
> >    
>
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