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Re: Class casting
Interestingly enough, if you did this:
int main() {
B b;
C* c = new C(b);
}
It will compile and work as expected. The constructor wants an A, a B is
an A, so everything is fine.
Why one needs to declare the B first, rather than instantiating the
temporary as in the code below, I have no idea. Can anyone shed some
light on this?
Justin
On Wed, 2003-07-02 at 12:09, Greg Davey wrote:
...
> int main(){
> C* c = new C(B());
> c->doOtherStuff();
> return 0;
> }
>