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[Bug c++/33972] Cannot declare operator() using function typedef
- From: "paolo at gcc dot gnu.org" <gcc-bugzilla at gcc dot gnu dot org>
- To: gcc-bugs at gcc dot gnu dot org
- Date: Tue, 24 Jun 2014 14:48:14 +0000
- Subject: [Bug c++/33972] Cannot declare operator() using function typedef
- Auto-submitted: auto-generated
- References: <bug-33972-4 at http dot gcc dot gnu dot org/bugzilla/>
https://gcc.gnu.org/bugzilla/show_bug.cgi?id=33972
--- Comment #3 from paolo at gcc dot gnu.org <paolo at gcc dot gnu.org> ---
Author: paolo
Date: Tue Jun 24 14:47:42 2014
New Revision: 211944
URL: https://gcc.gnu.org/viewcvs?rev=211944&root=gcc&view=rev
Log:
/cp
2014-06-24 Paolo Carlini <paolo.carlini@oracle.com>
PR c++/33972
* decl.c (grokdeclarator): Do not early check for operator-function-id
as non-function.
/testsuite
2014-06-24 Paolo Carlini <paolo.carlini@oracle.com>
PR c++/33972
* g++.dg/other/operator3.C: New.
* g++.dg/template/operator8.C: Adjust.
* g++.dg/template/operator9.C: Likewise.
Added:
trunk/gcc/testsuite/g++.dg/other/operator3.C
Modified:
trunk/gcc/cp/ChangeLog
trunk/gcc/cp/decl.c
trunk/gcc/testsuite/ChangeLog
trunk/gcc/testsuite/g++.dg/template/operator8.C
trunk/gcc/testsuite/g++.dg/template/operator9.C