[Bug c++/50056] Binding a temporary object to a reference

["redi at gcc dot gnu.org" <gcc-bugzilla at gcc dot gnu dot org>]

http://gcc.gnu.org/bugzilla/show_bug.cgi?id=50056

--- Comment #1 from Jonathan Wakely <redi at gcc dot gnu.org> 2011-08-12 12:46:42 UTC ---
Are you sure G++ isn't correct?
The cast creates a temporary reference, which binds to the temporary object,
then initalizes 's' with the temporary reference. That means the temporary
object's lifetime is extended to the same lifetime as the reference, but the
reference is temporary so is destroyed at the end of the full expression.

call S::S()
bind to temporary reference
initialize s from temporary reference
temporary reference goes out of scope
call S::~S()
call S::func()
s goes out of scope

if you do this:

const S& s = S();

then you get the behaviour I assume you are expecting:

call S::S()
initialize s temporary object
call S::func()
s goes out of scope
call S::~S()