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[Bug fortran/37536] [4.3/4.4 Regression] a mfcr is produced instead of branches for DO loops
- From: "pault at gcc dot gnu dot org" <gcc-bugzilla at gcc dot gnu dot org>
- To: gcc-bugs at gcc dot gnu dot org
- Date: 16 Sep 2008 15:29:21 -0000
- Subject: [Bug fortran/37536] [4.3/4.4 Regression] a mfcr is produced instead of branches for DO loops
- References: <bug-37536-6528@http.gcc.gnu.org/bugzilla/>
- Reply-to: gcc-bugzilla at gcc dot gnu dot org
------- Comment #5 from pault at gcc dot gnu dot org 2008-09-16 15:29 -------
(In reply to comment #2)
Hi Andrew,
Does this do it for you or is this all to rarified for this
Bear-of-little-brain to follow?
D.1359 = *start - *offset;
D.1360 = *end + *offset;
D.1361 = *step;
D.1364 = D.1361 > 0 ? D.1360 < D.1359 : D.1360 > D.1359; /* Fix the
result*/
if (D.1364) goto L.2; /* Then branch */
countm1.0 = (D.1361 > 0 ? (character(kind=4)) (D.1360 - D.1359) :
(character(kind=4)) (D.1359 - D.1360)) / (character(kind=4)) ABS_EXPR <D.1361>;
i = D.1359;
while (1)
Cheers
Paul
--
http://gcc.gnu.org/bugzilla/show_bug.cgi?id=37536