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Re: rshift problem


On Sun, May 18, 2008 at 11:24 AM, John Kacur <jkacur@gmail.com> wrote:
>  int main(void)
>  {
>         unsigned j = ~0 >> 8;

The above is signed right shift which will keep the sign bit and replicate it.
>         unsigned i = ~0;
>         i  >>= 8;
While this is an unsigned right shift.


-- Pinski


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