[Bug c++/34696] New: Overloaded template losing type in invoking a superclass method?

["mrsam at courier-mta dot com" <gcc-bugzilla at gcc dot gnu dot org>]

Given the following test program:

#include <sstream>
#include <iostream>

class X : private std::ostringstream {

public:

        template<typename a> X &operator<<(a arg)
        {
#if 0
                std::ostringstream &o= *this;

                o << arg;
#else
                std::ostringstream::operator<<(arg);
#endif
                return *this;
        }

        using std::ostringstream::str;
};

int main(int argc, char **argv)
{
        X x;

        x << "foo";

        std::cerr << x.str() << std::endl;
}


The output that I get is:

$ ./t
0x4014f0

... or some other hexadecimal pointer value.

If I change the "#if 0" to "#if 1" and compile the alternate version, I get the
expected results:

$ ./t
foo

After staring at this for a while, I can't see what the difference is here. It
almost looks like "std::ostringstream::operator<<(arg)" ends up invoking
std::ostringstream::operator<<(void *) even though arg's type is char * (or a
const char *).


-- 
           Summary: Overloaded template losing type in invoking a superclass
                    method?
           Product: gcc
           Version: 4.1.2
            Status: UNCONFIRMED
          Severity: normal
          Priority: P3
         Component: c++
        AssignedTo: unassigned at gcc dot gnu dot org
        ReportedBy: mrsam at courier-mta dot com
 GCC build triplet: x86_64-redhat-linux
  GCC host triplet: x86_64-redhat-linux
GCC target triplet: x86_64-redhat-linux


http://gcc.gnu.org/bugzilla/show_bug.cgi?id=34696